2x[x+3(x+1)]=

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Solution for 2x[x+3(x+1)]= equation: 


Simplifying
2x[x + 3(x + 1)] = 0

Reorder the terms:
2x[x + 3(1 + x)] = 0
2x[x + (1 * 3 + x * 3)] = 0
2x[x + (3 + 3x)] = 0

Reorder the terms:
2x[3 + x + 3x] = 0

Combine like terms: x + 3x = 4x
2x[3 + 4x] = 0
[3 * 2x + 4x * 2x] = 0
[6x + 8x2] = 0

Solving
6x + 8x2 = 0

Solving for variable 'x'.

Factor out the Greatest Common Factor (GCF), '2x'.
2x(3 + 4x) = 0

Ignore the factor 2.

Subproblem 1
Set the factor 'x' equal to zero and attempt to solve:

Simplifying
x = 0

Solving
x = 0

Move all terms containing x to the left, all other terms to the right.

Simplifying
x = 0

Subproblem 2
Set the factor '(3 + 4x)' equal to zero and attempt to solve:

Simplifying
3 + 4x = 0

Solving
3 + 4x = 0

Move all terms containing x to the left, all other terms to the right.

Add '-3' to each side of the equation.
3 + -3 + 4x = 0 + -3

Combine like terms: 3 + -3 = 0
0 + 4x = 0 + -3
4x = 0 + -3

Combine like terms: 0 + -3 = -3
4x = -3

Divide each side by '4'.
x = -0.75

Simplifying
x = -0.75
Solution
x = {0, -0.75}

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